1630 Arithmetic Subarrays - Medium
Problem:
A sequence of numbers is called arithmetic if it consists of at least two elements, and the difference between every two consecutive elements is the same. More formally, a sequence s
is arithmetic if and only if s[i+1] - s[i] == s[1] - s[0]
for all valid i
.
For example, these are arithmetic sequences:
1, 3, 5, 7, 9 7, 7, 7, 7 3, -1, -5, -9
The following sequence is not arithmetic:
1, 1, 2, 5, 7
You are given an array of n
integers, nums
, and two arrays of m
integers each, l
and r
, representing the m
range queries, where the ith
query is the range [l[i], r[i]]
. All the arrays are 0-indexed.
Return a list of boolean
elements answer
, where answer[i]
is true
if the subarray nums[l[i]], nums[l[i]+1], ... , nums[r[i]]
can be rearranged to form an arithmetic sequence, and false
otherwise.
Example 1:
Input: nums = [4,6,5,9,3,7]
, l = [0,0,2]
, r = [2,3,5]
Output: [true,false,true]
Explanation:
In the 0th query, the subarray is [4,6,5]. This can be rearranged as [6,5,4], which is an arithmetic sequence.
In the 1st query, the subarray is [4,6,5,9]. This cannot be rearranged as an arithmetic sequence.
In the 2nd query, the subarray is [5,9,3,7]. This
can be rearranged as [3,5,7,9]
, which is an arithmetic sequence.
Example 2:
Input: nums = [-12,-9,-3,-12,-6,15,20,-25,-20,-15,-10], l = [0,1,6,4,8,7], r = [4,4,9,7,9,10] Output: [false,true,false,false,true,true]
Constraints:
n == nums.length
m == l.length
m == r.length
2 <= n <= 500
1 <= m <= 500
0 <= l[i] < r[i] < n
-105 <= nums[i] <= 105
Problem Analysis:
-
iterate though the subarrays from the
zip(l,r)
pair -
core logic in is_arithmetic function
-
return true for the base case when all element is the same
-
else sort the array and find the first delta
-
return true if all delta is the same
-
Time Complexity
- O(Q * N * log N) where Q is the number of queries (length of
l
orr
) and N is the maximum length of the subarrays.- The solution involves iterating through each specified subarray and, for each subarray, performing sorting operations (O(N * log N)) inside the
is_arithmetic
function.
- The solution involves iterating through each specified subarray and, for each subarray, performing sorting operations (O(N * log N)) inside the
- O(Q * N * log N) where Q is the number of queries (length of
-
Space Complexity:
- O(N) for the sorted subarrays created inside the
is_arithmetic
function.- The space complexity is mainly due to the sorting operation inside the
is_arithmetic
function. The additional variables (is_arithmetic
,arr
,delta
) use constant space.
- The space complexity is mainly due to the sorting operation inside the
- O(N) for the sorted subarrays created inside the
Solutions:
class Solution:
def checkArithmeticSubarrays(self, nums: List[int], l: List[int], r: List[int]) -> List[bool]:
def is_arithmetic(arr):
if len(set(arr)) == 1:
return True
arr.sort()
delta = arr[1] - arr[0]
return all(y - x == delta for x, y in zip(arr, arr[1:]))
return [is_arithmetic(nums[left:right+1]) for left, right in zip(l, r)]